The perimeter of a rectangular parking lot is 346 m. If the width of the parking lot is 76 m, what is it’s length?

Answer 1

Perimeter = L + L + W + W

= 2L +2W

W= 76 m

P= 346 m

Plug these into Perimeter equation now.

P= 2L +2W

346 = 2L + 2(76)

346- 2(76) = 2L

346-152 =2L

194 = 2L

97= L

Answer 2

If x is the width and y is the length of the rectangle then 2x+2y=346. Since x=76 we obtain 152+2y=346 which implies that 2y=194 or y=97.

Answer 3

The formula for the perimeter of a rectangle is. . .

P = 2 * L + 2 * W

where P is perimeter, L is length, and W is width.

Your problem requires us to solve for L, given P and W.

We can first rearrange the formula to solve for L algebraically. . .

(P - 2 * W) / 2 = L

Then, filling the variables in with your given values, we can solve for L. . .

L = (346 - 2 * 76) / 2 = (346 - 152) / 2 = 194 / 2 = 97

The length is 97m.