J.R. S. answered 10/24/20
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
The answer should be (d), i.e. ni = 3. The Balmer series is for electrons in excited states transitioning to the n = 2, so 2 is nf not ni. The initial n would be 3 because 3->2 has a greater wavelength than 4->2 which is greater than 5->2 which is greater than 6->2
The associated wavelengths in the Balmer series are as follows:
3 -> 2 = 657 nm
4 -> 2 = 486 nm
5 -> 2 = 434 nm
6 -> 2 = 410 nm