Tom K. answered 10/24/20
Knowledgeable and Friendly Math and Statistics Tutor
If we allow LeBron to steal even on the first possession, if Anthony wins the flip, we can figure as follows
Probability that LeBron wins on the first possession (this includes both LeBron winning by winning the flip and stealing) : .5 * .5 + .5 * p * .5 = .25 + .25p
Probability that Anthony wins on the first possession: .5 * (1-p) * .5 = .25 - .25p
After the first shot, each has equal probability on each shot given that they have possession, and Anthony always gets the rebound, so the probability that Anthony wins after the first shot, given that there is another shot, is 1 - p, and the probability that LeBron wins is p. There is .5 probability that there is no win on the first shot. Thus, using LeBron's probability,
.25 + .25p + .5p = .5
.25 + .75p = .5
.75 p = .25
p = 1/3
Note that, for Anthony, .25 - .25p + .5(1 - p) = .75 - .75p = .75 - .75(1/3) = .5
(If we did not allow LeBron to steal on the first possession, p = .5)