What is the equation in Slope intercept form that is perpendicular to x - 4y = 8 that goes through (1,1)

Answer 1

first thing is to re write the original equation in y= mx +b form so we can identify its slope

So x-4y=8 becomes -4y=8-x Y= =-2 +(x/4) So slope of this line is 1/4

A line which is perpendicular to this line will have a slope which is the negative reciprocal of 1/4 which would be -4( to get the negative reciprocal turn the fraction upside down and change the sign)

So the equation of the new line is y=-4x+b You can now use the point (1,1) to solve for b

1= -4(1) +b. B=5

so equation of the perpendicular line is y= -4x+5