J.R. S. answered 10/16/20
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
NaOH(aq) + HCl(aq) ==> NaCl(aq) + H2O(l) ... balanced equation for neutralization
q = mC∆T where q = heat; m = mass; C = specific heat; ∆T = change in temperature
25 ml 2 M NaOH + 25 ml 2 M HCl = 50 mmol NaOH + 50 mmol HCl => 50 mmole H2O ∆H = x
25 ml 1 M NaOH + 25 ml 1 M HCl = 25 mmol NaOH + 25 mmol HCl => 25 mmole H2O ∆H = 1/2x
The measured temperature change will be twice as great for the first reaction compared to the second reaction because twice as many moles are reacting and twice as many moles of product are produced. So answer (c).