mean = 236.3 (sum all the values and divide by the number of values)
SD = 37.55 (sum of (value - mean)^2)/number of values
mean - 3 SD = 236.3 - 3 * 37.55 = 123.65
(235 - 236.3)/37.55 = -0.035, so 0.035 SD below the mean
Gracie A.
asked 10/13/20Following are the published weights (in pounds) of all of the team members of Football Team A from a previous year.
174, 176, 178, 184, 185, 185, 185, 185, 188, 190, 200, 202, 205, 206, 210, 211, 211, 212, 212, 215, 215, 220, 223, 228, 230, 232, 241, 241, 242, 245, 247, 250, 250, 259, 260, 260, 265, 265, 270, 272, 273, 275, 276, 278, 280, 280, 285, 285, 286, 290, 290, 295, 302
Assume the population was Football Team A.
I need help finding the following. (I have to round the answers to two decimal places.)
(i) the population mean, μ
(ii) the population standard deviation, σ
(iii) the weight that is 3 standard deviations below the mean
(iv) When Player A played football, he weighed 235 pounds. How many standard deviations above or below the mean was he?
mean = 236.3 (sum all the values and divide by the number of values)
SD = 37.55 (sum of (value - mean)^2)/number of values
mean - 3 SD = 236.3 - 3 * 37.55 = 123.65
(235 - 236.3)/37.55 = -0.035, so 0.035 SD below the mean
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Gracie A.
I get it now, thank you for taking the time to explain this problem to me, this helped a lot! Have a great night10/13/20