How many mL of stomach acid would be neutralized by the antacid?

Question

If 1.95 x 10-3 mols of stomach acid is neutralized by the antacid, and the concentration of stomach acid is 0.155 M, how many mL of stomach acid would be neutralized by the antacid?

a. 13.4 mL

b. 13.8 mL

c. 13.0 mL

d. 12.6 mL

I personally think the answer is D: 12.6 mL. I'm unsure if I'm correct.

Answer 1

(x L)(0.155 mol/L) = 1.95x10-3 moles

x = 0.01258 L = 12.6 mls