J.R. S. answered 10/10/20
Ph.D. in Biochemistry with an emphasis in Neurochemistry/Neuropharm
Heat lost by brass must equal heat gained by water
Heat lost by brass = q = mC∆T = (47.0 g)(0.375 J/gº)(83.3 - Tf) where Tf is final temperature of water
Heat gained by water = q = mC∆T = (300.0 g)(4.184 J/gº)(Tf - 15.0º)
Setting these two equal we have...
(47.0 g)(0.375 J/gº)(83.3 - Tf) = (300.0 g)(4.184 J/gº)(Tf - 15.0º)
1469 - 17.6Tf = 1255Tf - 18,828
1273Tf = 20297
Tf = 15.9ºC = equilibrium temperature of water