
William W. answered 10/10/20
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The volume of a right square pyramid is (1/3)x2h where x is the side length of the base. So in this case, since h = x - 2, then V = (1/3)x2(x - 2). Since we are told the volume is 3 then:
3 = (1/3)x2(x - 2)
9 = x2(x - 2)
9 = x3 - 2x2
x3 - 2x2 - 9 = 0
To determine the POSSIBLE rational zeros, we can use the rational roots theorem which says that if there are any rational roots, they would be ± the factors of the constant term divided by the leading coefficient so 9 divided by 1, or in other words ±1, ±3, ±9.
Using synthetic division, we find the solution to be x = 3, so the sides of the base are 3 and the height is 1.