A rectangular room measures 15 feet by 7 feet. Find the cost of installing a strip of wallpaper around the room if the wallpaper costs $ 0.95 foot.

Question

A rectangular room measures 15 feet by 7 feet. Find the cost of installing a strip of wallpaper around the room if the wallpaper costs $ 0.95 foot. 

Answer 1

Find the perimeter .

30+14=44ft.

44x.95=41.8

The total cost is $41.80.

Answer 2

Hi Michael,

here first you have to find Perimeter of the rectangular Room , because strip of the paper will be surrounded the room .

so you know the formula of the Perimeter of a Rectangle is = 2* ( L + W )

So the Perimeter of that ractangular Room = 2* ( 15 + 7 ) ft

= 44 Ft.( unit of perimeter is always in ft not in sqare ft )

So per ft it costs $.95 ,

44 ft it will cost 44* $.95 = $ 41.8

Hence , the total cost to install the strip of the paper is $ 41.8 Ans

Answer 3

Since the room is rectangular, the perimeter of the room is P = 2 * L + 2 * W = 2 * (L + W).

Here, let L = 15 ft and W = 7 ft; then P = 2 * (15 ft + 7 ft) = 2 * 22 ft = 44 ft.

Now a strip of wallpaper around the room (around the perimeter) that costs $0.95 / ft would cost

$0.95 / ft * P = $0.95 / ft * 44 ft = $41.80.

Answer 4

To find the cost you need to use the measurements of the room to find the perimeter (distance around the outside). The room measures 15 by 7 feet, and since it's rectangular, we know that there are two parallel walls with each length. The perimeter can be calculated as (15 x 2) + (7 x 2) = 44 feet. Multiply 44 feet by the cost per foot of $0.95, and the total cost to put a strip of wall paper around this room is $41.80.