what is the result when 3(2x-5) is added to 2(4-x)

Answer 1

Problem: 3(2x-5) + 2(4-x) = ?

When we look at these problems, we notice we have an integer, also known as a number, outside a pair of parentheses. For this, we must use the distributive property that allows us to multiply the integer to all values inside the parentheses.

Step 1:

(3*2x - 3*5) + 2(4 - x) = ?

(3*2x - 3*5) + (2*4 - 2*x) = ?

Now that we have distributed the 3 and the 2, we can just multiply all the numbers together to make it look a little cleaner.

Step 2:

(6x-15) + (8-2x) = ?

For this step, we can remove the parenthesis and rearrange the values so that the x's are with the x's and the numbers are with the numbers. And then we just solve.

Step 3:

6x - 15 + 8 - 2x = ?

6x - 2x - 15 + 8 = ?

4x-7 = ?

This last answer, 4x-7, cannot be reduced down further, because they both do not have the variable "x".

Answer: 4x-7

Answer 2

You want to solve each side of the addition sign separately THEN combine them.

3(2x-5) + 2(4-x)

Use Order of operations (PEMDAS) to solve. Parentheses, Exponents, Multiply or Divide, Add or Subtract.

3(2x-5)

First we want to clear the parentheses by using the distributive property. The distributive property tells you to multiply everything on the outside by everything on the inside of the parentheses individually.

(3*2x) - (3*5) which gives you 6x-15 (LEFT SIDE DONE)

RIGHT SIDE

2(4-x) Use PEMDAS and the distributive property again.

(2*4) - (2*x) which gives you 8-2x (RIGHT SIDE)

Now you combine both sides' like terms.

Left side + Right side

6x-15 + 8 - 2x

(6x-2x) + (-15+8)

Answer: 4x-7