Calculate the new temperature of the water bath.

Question

A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 9.90kg

of water at 38.0°C. During the reaction 140.kJ of heat flows out of the flask and into the bath.

Calculate the new temperature of the water bath.

You can assume the specific heat capacity of water under these conditions is 4.18·J·g−1K−1.

Be sure your answer has the correct number of significant digits.

Answer 1

9.90 kg = 9900 g

q = mC∆T

140 kJ = (9900 g)(4.18 J/gº)(∆T)

∆T = 140,000 J/(9900 g)(4.18 J/gº)

Solve for ∆T and add it to 38º to get final temp (use 3 sig. figs.)