What will be the final temperature of the Aluminum bar and of the water once thermal equilibrium is achieved ?

Question

A 10.0 g bar of aluminum initially at  is placed in 100.mL of water initially at  .

What will be the final temperature of the Aluminum bar and of the water once thermal equilibrium is achieved ?

The specific heat capacities of Al and water are 0.902 J/gC and 4.184 J/gC respectively.

Answer 1

This one is a little different than the others, so I'll try to guide you through.

heat lost by Al must equal heat gained by H2O

mC∆T for Al = mCT for H2O

(10.0 g)(0.902 J/gº)(95º-Tf) = (100 g)(4.184 J/gº)(Tf-25º) where Tf = final temperature

856.9 - 9.02Tf = 418.4Tf - 10,460

427Tf = 11317

Tf = 26.5ºC final temperature