Tom K. answered 10/07/20
Knowledgeable and Friendly Math and Statistics Tutor
You can select 4 of 8 rap videos and 3 of 6 R&B videos in C(8,4) x C(6,3) ways. As we are playing 7 videos, and order matters, there are 7! orders in which they may be played.
Thus, C(8,4) x C(6,3) x 7! = 70 * 20 * 5040 = 7056000
As there are 19 questions that can be answered or not answered, there are 2^19 possible ways to select them. However, as we must select at least two, we subtract the number of ways that you can select 0 (1) or1(as there are 19 questions, 19)
Thus, 2^19 - 19 - 1 = 2^19 - 20 = 524268
i) E, the car is blue , and G, the car is a green Ford. As being blue and green are mutually exclusive, and G is a subset of the set of green cars, E and G are mutually exclusive
ii) G and E U F If G is mutually exclusive of E and G is mutually exclusive of F, G is mutually exclusive of E and F. From i), we know that it is mutually exclusive of E. F is a car is a Toyota and G is a car being a green Ford. As being a Toyota and being a Ford are mutually exclusive, E and G are mutually exclusive.
Thus, G is mutually exclusive of E and F, so G is mutually exclusive of E U F
iii) We make the assumption here that E contains at least one member. Then, the complement of being a green Ford is not being green or not being a Ford. Then, being blue is a subset of not being green, so E is a subset of G', and E is a subset of F' U G'. Thus, E and F' U G' are not mutually exclusive.