The equation for exponential growth is
y= A(e^kt). where A is initial value, k is growth constant and t is time
5.9= 3.0(e^25k)
(5.9/3)= e^25k. Now take natural log of both sides
ln(1.997)= ln (e^25k)
ln 1.997= 25k
k= ln1.997/25
k=.027= 2.7%
Mike J.
asked 10/03/20A CT scan shows that the patient has a 3 cm tumor. After 25 days, the size of the tumor has has increased to 5.9 cm. What is the growth rate?
b = Answer (round to the nearest hundredth)
Percentage = Answer% (no decimal places)
The equation for exponential growth is
y= A(e^kt). where A is initial value, k is growth constant and t is time
5.9= 3.0(e^25k)
(5.9/3)= e^25k. Now take natural log of both sides
ln(1.997)= ln (e^25k)
ln 1.997= 25k
k= ln1.997/25
k=.027= 2.7%
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.