Area = pi r^2 Take the derivative of both sides With respect to time
da/dft= 2pir dr/dt
you want to solve for da/dot which how fast the area is changing when r=8 and you are given dr/et=3
so da/dt= 2pi(8)(3) = 48pi ft/second
Robert X.
asked 10/02/20A pebble falls in a pond and the ripples spread out in a circular pattern. If one circular ripple
spreads out such that the radius grows by 3 feet/second, how fast is the circle’s area increasing
when the radius is 8 feet long? Leave your answer in terms of π .
Area = pi r^2 Take the derivative of both sides With respect to time
da/dft= 2pir dr/dt
you want to solve for da/dot which how fast the area is changing when r=8 and you are given dr/et=3
so da/dt= 2pi(8)(3) = 48pi ft/second
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