The length of a rectangle is three more than twice the width. The perimeter is 98. What are the dimensions?

Answer 1

L=length

W=width

P=perimeter

We know,

1. L=3+2W
2. P=2L+2W

First plug in our perimeter and factor out the 2,

98=2(L+W)

49=L+W

Now, substitute equation 1 in for L,

49=(3+2W)+W

49=3+3W

46=3W

46/3=W

Plug in W=46/3 into equation 1 to find L,

L=3+2(46/3)

L=3+(92/3)

L=(101/3)

Finally plug L and W into equation 2 to check our work,

98=2(101/3)+2(46/3)

98=(202/3)+(92/3)

98=(294/3)

98=98

Therefore our answers are,

1. L=101/3
2. W=46/3

Answer 2

Hi,

The length of a rectangle is three more than twice the width. The perimeter is 98. What are the dimensions?

length = L and width = W

Base of given information: L = 3 + 2W

perimeter : 2L + 2W = 98

Now, replace L = 3 + 2W in the equation of 2L + 2W = 98

2( 3 + 2W ) + 2W = 98

6 +4w + 2W = 98

6W = 92

W = 92/6 = 46/3

L= 3+ 46/3 = 55/3

I hope it is useful.

Minoo