J.R. S. answered 09/21/20
Ph.D. in Biochemistry with an emphasis in Neurochemistry/Neuropharm
q = mC∆T
q = heat = ?
m = mass = 25 g
C = specific heat = 4.184 J/gº
∆T = change in temperature = 25º (it went from 25º to 0º)
q = (25 g)(4.184 J/gº)(25º)
q = 2615 J = 2.62 kJ
We can find the moles of NH4NO3 from the ∆Hsoln as follows:
2.62 kJ x 1 mole/25.7 kJ = 0.102 moles NH4NO3 must have been present
Converting this to grams, we have... 0.102 mole NH4NO3 x 80.1 g/mol = 8.17 g NH4NO3