Help plz this is urgent

Question

The perimeter of a parallelogram must be no less than 40 feet. The length of the rectangle is 6 feet. What are the possible measurements of the width?

1. Write an inequality to represent this problem. Use w to represent the width of the parallelogram. [Hint: The formula for finding the perimeter of a parallelogram is P = 2l + 2w.
2. What is the smallest possible measurement of the width? Justify your answer by showing all your work.

Answer 1

Perimeter of parallelogram = P = 2(X+Y) where X is the length of 2 sides opposite each other and Y = the length of the other 2 sides. Or use L and W for length of 2 sides and W for the other 2 sides

But that's not exactly accurate, as a very flat enlongated parallelogram extends far longer than L and far shorter than W. But if the parallogram is a rectangle, then L and W are the length and width of the parallelogram.

2(L+W)>40

IF the parallelogram is a rectangle, then L=6 means

2(6+W)>40

12+2W>40

2W>40-12=28

W>28/2 = 14

W>14 feet

14 feet is the smallest W can be, such that the perimeter is 40 or more