Inactive Tutor answered 09/24/20
Mary, here's how I would tackle this.
tan(-5π/3) = tan(-5π/3 + 2π) . . . . . since the value of tan repeats every kπ radians, for k = 0, ±1, ±2, . . .
= tan(π/3)
= √3
Mary C.
asked 09/18/20show works please
Inactive Tutor answered 09/24/20
Mary, here's how I would tackle this.
tan(-5π/3) = tan(-5π/3 + 2π) . . . . . since the value of tan repeats every kπ radians, for k = 0, ±1, ±2, . . .
= tan(π/3)
= √3
tan (-5pi/3) is the same as tan pi/3
If you go in the - 5pi/3 direction you make nearly one
full rotation clockwise. A full rotation would be 2pi
or 6pi/3 so -5pi/3 is pi/3 short of this
tan pi/3 =sqroot 3
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