use the vertex (h, k) and a point on the graph (x, y) to find the general form of the equation of the quadratic function

Question

(h, k) = (3, 2), (x, y) = (10, 1)

Answer 1

Ooyeon

The vertex form is a(x-h)² + k

So here y = a (x-3)² + 2

When x = 10, y =1 , so 1 = a . 7² + 2 so -1 = 49a, so a = -1/49

So y = (-1/49) (x-3)² + 2

If you need the standard form expand the squared bracket

y = (-1/49) (x² - 6x + 9) + 2 = (-1/49) x² + (6/49) x + ( 2 - 9/49)

Mike