Gilberto S. answered 09/16/20
I've spent more 12+ years teaching college level mathematics
I found it helpful to break down a couple of different possibilities. If all we know is that there are 4 volunteers who are either male or female, then you could have:
4 males
3 males, 1 female
2 males, 2 females
1 male, 3 females
4 females.
But since we are told that there is at least one male and at most 1 female, only the first two rows are possible. So basically we have two cases to consider:
How many ways are there to choose 4 males out of 13? C(13,4)
And how many ways are there to chose 1 female out of 7 and at the same time choose 3 males out of 13?
7 • C(13,3)
So to find the answer you just need to calculate:
C(13,4) + 7 • C(13,3)
Michael K.
I meant to say I got part A wrong and the answer was suppose to be 4810. Sorry for the typo!09/16/20
Michael K.
Thank you so much for the information! So for part A for the at least 1 male part, would I take C(20,4) then subtract C(7,4)? My answer for part A is 4810. I got the 2nd part for the female which added up to 2717 but I can't seem to understand the first part!09/16/20