Arthur D. answered • 09/14/20

Forty Year Educator: Classroom, Summer School, Substitute, Tutor

this is a combination not a permutation

it doesn't matter which entree is put in the plate first

you can choose 2 entrees from 5 entrees

use the formula n!/((r!)(n-r)!) where n=5 and r=2

5!/(2!*3!)

(5*4*3*2*1)/(2*1*3*2*1)=

(5*4)/2=

20/2

10 combinations

Joss E.

Thank you so much!09/14/20