I think you're looking to graph 4x-2. This graph y=4x has a critical point at (0,1), as do all graphs of the form y = nx, where n is any real number. It has an asymptote at y=0, which is the x-axis, on the left side of the graph. Try making a table for some negative and positive values around zero if you don't understand why. (Raising 4 to the -1 power = 1/4, and 4-2= 1/16. The negative exponent "flips" the answer.) After penciling in this graph, the -2 part lowers all your function (y) values by two. So the asymptote is now at y=-2, and the point that was at (0,1) is now at (0,-1). Also, if x=1, you would have 41=4, but adding the "-2" to the equation means that 41-2 = 4 - 2=2. So you'll also have a point at (1,2). If you need a good graph, try desmos.com.
I hope that helps, and let me know if you have any questions?