general equation of the parabola with vertex (-4,3), with vertical axis of symmetry and passes through (0,-1)

Answer 1

It opens downward since the point is below the vertex, so the coefficient of the x^2 term is negative

x has the quadratic term since the line of symmetry is vertical

y-k=-a(x-h)^2 with (h,k)=(-4,3) and (x,y) = (0,-1)

plug in the values and solve for a

-1-3 = -a(0+4)

-4 = -4a

a=1

y-3 =-(x+4)^2 is the general equation for the parabola