Construct a 98​% confidence interval estimate of the standard deviation of body temperature of all healthy humans.

Question

A simple random sample from a population with a normal distribution of 97 body temperatures has x=98.10°F

and s=0.65°F.

Construct a 98​% confidence interval estimate of the standard deviation of body temperature of all healthy humans.

Answer 1

The formula to calculate confidence interval = M ± z∗√s²/n

Given information:

1. z at 98% confidence interval = 2.326
2. M or mean = 98.1
3. n or sample size = 97
4. s or standard deviation = 0.65

Therefore, Confidence Interval = 98.1 ±2.326∗√(0.65)²/97 = or 98.1 ± 0.15

i.e., You can be 98% confident that the population mean falls between 97.95 and 98.25