
Patrick B. answered 08/02/20
Math and computer tutor/teacher
2)
For quadratic equaton ax^2+bx+c=0, The discriminant is b^2-4ac.
If the discriminant is zero, then the equation has only one solution,
namely -b/(2a)
if the discriminant is a positive perfect square, then the
equation as TWO RATIONAL SOLUTIONS. In THIS CASE, the equation
can be factored
if the discriminant is a positive NON-perfect square, then
the equationhas TWO REAL (but irrational) solutions
containing radicals
if the disciminant is NEGATIVE, ask you have asked,
then the equation has TWO imaginary/complex solutions
#1)
(b)
x^2 + 5x+ 6 = 0 is best solved by factoring (x + 3)(x+2 ) = 0
is easy to factor. Always check if it can be factored.
(c) x^2 = 81 is best solved by square root method as the
calculation of the square root is easy. If A=1 C is a negative
perfect square , then the square root method is easy.
(d) x^2 + 4x = 11 is best solved by completing the square because
B is an even integer. If A=1 and B is an even number, then it
is easy to complete the square
(e) otherwise you use the quadratic formula

Mark M.
If the discriminant is zero there are two identical roots.08/02/20