Fizaa A.

asked • 07/30/20

Please helpp!!!!

If one eigenvalue of a 2 by 2 matrix LaTeX: E_{2 \times2}  is  LaTeX: \lambda = {\vec i}   and a corresponding eigenvector of LaTeX: {\vec i}  is

LaTeX: {\vec v} = \left(\begin{array}{r} 1\\ \\ {\vec i} \end{array}\right)   , then the general solution of the system ODEs:

LaTeX: {\vec x^{\prime} (t)} = E_{2 \times 2} \cdot {\vec x(t)}


A.)is  LaTeX: {\vec x(t)} = C_1 \cdot \left[\begin{array}{c} \cos t\\ \\ \sin t \end{array}\right] \, + \, C_2 \cdot \left[\begin{array}{c} \sin t\\ \\ \cos t \end{array}\right]

B.) can't be determined. Solving the system requires additional information.

C.)is LaTeX: {\vec x(t)} = \left[\begin{array}{c} \sin t \\ \\ \cos t \end{array}\right] \, + \, C_2 \, \left[\begin{array}{c} \cos t\\ \\ \sin t \end{array} \right]

D.) is LaTeX: {\vec x(t)} = C_1 \cdot \left[\begin{array}{c} \cos t\\ \\ - \, \sin t \end{array}\right] + C_2 \, \left[\begin{array}{c} \sin t \\ \\ \cos t \end{array} \right]


I think its either C or D. 


1 Expert Answer

By:

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.