
Sam Z. answered 07/31/20
Math/Science Tutor
I'm using an interest formula:
fv=p(1+int/c)^(nt)
future value
principal
int
compound .5/yr?
yrs
times/yr
fv=8000(1+.14/.5)/(4*.5)
=$13,107.20
Or is it 2/yr?
=$13745.49
Ledjnx E.
asked 07/30/20Eric borrowed $8000 at a rate of 14%, compounded semiannually. Assuming he makes no payments, how much will he owe after 4 years?Do not round any intermediate computations, and round your answer to the nearest cent.
$_______
Sam Z. answered 07/31/20
Math/Science Tutor
I'm using an interest formula:
fv=p(1+int/c)^(nt)
future value
principal
int
compound .5/yr?
yrs
times/yr
fv=8000(1+.14/.5)/(4*.5)
=$13,107.20
Or is it 2/yr?
=$13745.49
William W. answered 07/30/20
Top ACT Math Prep Tutor
The equation that models this situation is:
A(t) = A0(1 + r/n)nt
where:
A is the amount he owes at any time (t)
A0, is the initial amount borrowed (the amount owed at time t = 0)
n is the number of times the loan is compounded annually (in this case n = 2)
r is the interest rate in decimal form (in this case r = 0.14)
So A(4) = 8000(1 + 0.14/2)2•4
A(4) = 8000(1 + 0.07)8
A(4) = 8000(1.07)8
A = $13,745.49
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