Tom K. answered 07/30/20
Knowledgeable and Friendly Math and Statistics Tutor
To get the P(7), we get the probability that x is between 6.5 and 7.5, or p-hat is between
6.5/20 = .0325 and
7.5/20 = .0375
SE = sqrt(.33*(1-.33)/20)
Then,P(7) = P((.325-.33)/(sqrt(.33*(1-.33)/20)) <= z <= P((.375-.33)/(sqrt(.33*(1-.33)/20))) =
Φ(0.427989525480826) - Φ(-0.0475543917200918) = , i n Excel,
norm.s.dist(0.427989525480826,1) - norm.s.dist(-0.0475543917200918,1) =
0.184634936296571 By the way, the ,1 says that we are using the cumulative probability, not the density.
The actual probability is, again using Excel, binom.dist(7,20,.33,0) = 0.181127243698391
Note that we switched to the ,0, as we have exactly 7.
The normal approximation is 0.184634936296571
The exact probability is 0.181127243698391