
Patrick B. answered 07/24/20
Math and computer tutor/teacher
1) multiplication
2)
(B^k)^n
= (B^k) * (B^k) * (B^k) * ...* (B^k) <-- there are N factors of B^k
each of these factors contains K factors of B...
therefore there are k*N factors of B , which is B^(n*k)
3)
2^3 * 3^4 2^3 * 3^4 2^3 3^4
------------- = -------------- = -------- * --------- <--- splits into 2 fractions
4 * 3^5 2^2 * 3^5 2^2 3^5
= 2^(3-2) * 3^(4-5) <-- quotients: SUBTRACTS the exponents
= 2^(1) * 3^(-1)
= 2 * 1/3 <--- property of negative exponents
= 2/3