Find the equation of a line that is perpendicular to y=25- x/2 and intersects the point (7, 3)

Question

Find the equation of a line that is perpendicular to y=25- x/2 and intersects the point (7, 3)

Answer 1

The slope of the perpendicular will be the negative reciprocal of the original equation. The negative reciprocal of -1/2 is +2/1 or 2 so the equation of the perpendicular is y= 2x +b Using the point (7,3) you can now solve for b

3= 2(7) +b

3= 14 +b

b=-11

so equation is y = 2x-11