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Question

Consider the given reaction.

A(aq)+B(s)↽−−⇀C(aq)𝐾=9.40

Suppose  13.7 mol A  reacts with excess  B  in  5.90 L  of solution. Calculate the concentration of  C  at equilibrium.

Answer 1

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Answer 2

Set up an ICE table:

A(aq) + B(s) <==> C(aq) [A] = 13.7 mol/5.90 L = 2.32 M

2.32......0..............0.......Initial

-x.........................+x......Change

2.32-x..................x.......Equilibrium

K = [C]/[A] (NOTE: B is not included in the equilibrium expression b/c it is a solid)

9.40 = x/2.32-x

21.8 - 9.40x = x

10.40 x = 21.8

x = 2.098 = 2.10 M = [C] at equilibrium