Compound interest: A = P (1 + r/n) nt , where P = principal (400), r = rate = 0.021, n = how often compounded a year (12) and t = duration in years (6).
A = 4000 (1 + 0.021/12)^(12*6) = 4536.63
Jnkm .
asked 06/16/20Christine deposited $4000 into an account with 2.1% interest, compounded monthly. Assuming that no withdrawals are made, how much will she have in the account after 6 years?
Do not round any intermediate computations, and round your answer to the nearest cent.
$_____________
Compound interest: A = P (1 + r/n) nt , where P = principal (400), r = rate = 0.021, n = how often compounded a year (12) and t = duration in years (6).
A = 4000 (1 + 0.021/12)^(12*6) = 4536.63
Yefim S. answered 06/16/20
Math Tutor with Experience
A = P(1 + r/n)nt, where P = $4000, r = 2.1% = 0.021, n = 12 and t = 6 years.
We get A = 4000(1 + 2.1/12)12·6 = $4536.63·
David H. answered 06/16/20
MS3 student for Math and Science Tutoring
So lets break this question down into its components:
our equation that we will be using is the compound interest equation:
Y=P(1+ r/n )nt plugging in what we know we get
Y=4,000(1+ 0.021/12)6(12) = 4,536.63 extra was made so after a total of 6 years she made $8,536.63
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