
Brandon R. answered 06/16/20
Experienced Algebra and Geometry Tutor
Let's look at this problem as two separate parts.
Part 1: number of questions
Part 2: number of points
Part 1:
We know that there are 20 questions total. These questions are made up of T/F and multiple choice questions. To represent T/F, lets use x. To represent MC, let's use y.
x = number of T/F
y = number of MC
x + y = 20
Part 2: The total amount of points is 100. T/F questions are worth 3 points, and MC questions are worth 11 points. Since x represents the number of T/F questions, we multiply 3 and x to get the points earned on T/F questions. We also multiply 11 and y for MC.
3x + 11y = 100
Our system is as follows:
x + y = 20
3x + 11y = 100
You may solve this any way you would like. I will show substitution below:
The first equation can be rearranged by subtracting y from both sides. You get x = 20 - y. Let's substitute 20 - y in for x in the second equation.
3 (20 - y) + 11y = 100
Distribute 3 to 20 and -y
60 - 3y + 11y = 100
Combine -3 and 11y
60 + 8y = 100
Subtract 60 from both sides
8y = 40
Divide both sides by 8
y = 5
This means that there were 5 Multiple Choice questions on the test.
Tam H.
Thank you so much!06/16/20