sin2x = cosx
2sinxcosx = cosx
2sinxcosx - cosx = 0
cosx(2sinx - 1) = 0
cosx = 0 or sinx = 1/2
cosx = 0 when x = PI/2, 3/2 PI
sinx = 1/2 when x = PI/6 and 11/6 PI
Valesia S.
asked • 05/31/20Solve for 0 ≤ θ < 2π.
sin 2θ= cos θ
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Larry S.
Note: sinx = 1/2 when x = PI/6 and 5/6 PI05/31/20