How can I write a quadratic equation from these 3 points?

Question

(3, -10), (4,0), and (6,8)

Answer 1

The general form of the quadratic equation is y = ax2 + bx + c where a,b,c are constants.

So, substitute the points into the equation to get 3 equations and 3 unknowns

-10 = a(9) + b(3) + c

0 = a(16) + b(4) + c

8 = a(64) + b(8) + c

Then solve for a,b,c which will be a = -1.6, b = 21.2, & c = -59.2