Find sin ( u 2 ) if csc u = 11.008 and u is in Quadrant-I (assume that 0 < u < 2 π ).

Question

if someone could show the process of how to get the answer for this

Answer 1

sin is 1/csc

so sin(u) = 1/11.008

sin^2 = (1/11.008)^2 = .008

Answer 2

sin u = 1/11.008.

Look up the arcsin of that number (in radians!!).

Square the arcsin value and look up the sin of that.