mean 6, range 7, mode 3, median 6, six values
3, 3, 3, 9, 10 are six values that have range 10-3=7, mode 3 as most frequent, median = average of middle two = (3+9)/2=6
mean = sum/n = (3+3+3+9+10)/6 = 35/6 = 5 5/6 = 6 rounded to nearest integer, close but no cigar
there has to be two or three 3's for mode = 3. four, five, or six 3's won't work as then median=3 not 6
3,3,5,7, 8 ,10 are six values with range 7, median (5+7)/2 = 6, mode=3 mean (3+3+5+7+8+10)/6=36/6=6 BINGO. That's the solution. There may be more solutions, but that seems doubtful.
