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Yolanda J.

asked • 05/19/20

Tetrahydrocannabinol (thc), the active agent in marijuana, is composed of 80.16% carbon, 9.63% hydrogen and 10.17% oxygen by mass. What is the empirical formula of thc?

The answer I got was C7H10O, however I think I am missing a step since my answer was incorrect.


This is what I did

80.16g C (1mol/12.01g)C =7 mol C

9.63g H (1mol/1.008g)H =10mol H

10.17g O (1mol/16.00g)O =0.6= 1 mol O


therefore said the empirical formula was => C7H10O


can someone please tell me what I'm doing wrong?

1 Expert Answer

By:

Stanton D. answered • 05/19/20

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