Tetrahydrocannabinol (thc), the active agent in marijuana, is composed of 80.16% carbon, 9.63% hydrogen and 10.17% oxygen by mass. What is the empirical formula of thc?
The answer I got was C7H10O, however I think I am missing a step since my answer was incorrect.
This is what I did
80.16g C (1mol/12.01g)C =7 mol C
9.63g H (1mol/1.008g)H =10mol H
10.17g O (1mol/16.00g)O =0.6= 1 mol O
therefore said the empirical formula was => C7H10O
can someone please tell me what I'm doing wrong?