Peter G. answered 05/19/20
Patient and Experienced High School and College Math Tutor
Hello Cameron, here's my perspective.
A perfect square has the form (kx + b)2, which expands to k2x2 + 2kbx + b2. So, for question 1, we must add something to x2 + 12x so the result has the form k2x2 + 2kbx + b2. Let's assume we want to add just a constant c and no extra "x" term. Then, we want c such that x2 + 12x + c has the form k2x2 + 2kbx + b2. Matching the squared terms gives k=1. Then, matching the x terms while using k=1 gives b=6. Last, matching the constant terms using b=6 gives c=36. So, we must add 36 to x + 12x to make it a perfect square.....the perfect square (x + 6)2.
You can solve #2, 4, and 5 using this same reasoning. Here are the answers you'll get:
#2 Add 8
#4 c = 49
#5 (2x - 7)2
As for #3, you're asked to solve x2 - x + 3/16 = 0 by completing the square. This means you must first find a number c such that x2 - x + c is a perfect square. Based on the above discussion, we know that c=1/4, and the perfect square is (x - 1/2)2. Next, use this knowledge to solve x2 - x + 3/16 = 0 by completing the square as follows:
x2 - x + 1/4 - 1/4 + 3/16 = 0. (Add and subtract c)
(x - 1/2)2 - 1/4 + 3/16 = 0. (Express x2 - x + 1/4 as a perfect square)
(x - 1/2)2 - 1/16 = 0. (Simplify the numbers)
(x - 1/2)2 = 1/16 (Move the number to the right side)
(x - 1/2) = 1/4 or -1/4 (Square root both sides)
x = 1/2 + 1/4 or x = 1/2 - 1/4 (Solve for x)
x = 3/4 or x = 1/4
I hope that helped!