Rationalise the denominator of 6 / sq.rt. 7 -2

Question

Rationalise the denominator of 6 / √7 -2

Show your working clearly

Answer 1

Multiply and divide by √7 + 2.

6 / (√7 - 2) = [6 / (√7 - 2)] [(√7 + 2) / (√7 + 2)]

= 6(√7 + 2) / [(√7 - 2)(√7 + 2)]

= 6(√7 + 2) / (7 - 4)

= (6/3) (√7 + 2)

= 2 (√7 + 2)