There exists 5 consecutive numbers such as twice the fourth is equal to the second number increased by 11. What is the value of the largest number?

Question

I need to know what it is exactly.

Answer 1

Five consecutive numbers are going to be:

x , (x+1) , (x+2) , (x+3) , (x+4)

Now twice the fourth is equal to the second number increased by 11:

Fourth number is (x+3), twice the fourth is: 2(x+3)

The secomd number is: (x+1), increased by 11 is : (x+1)+11

Now make them equal to each other:

2(x+3) = (x+1)+11

2x+6 = x+12

Group like terms in each side of the equation:

2x-x = 12-6

Combine liked terms and solve for "x"

x=6

What is the value of the largest number?

The larger number is (x+4)

Substitute the "x"

Larger number = 6+4 = 10