
Arturo O. answered 04/27/20
Experienced Physics Teacher for Physics Tutoring
(A)
h(t) = -16t2 + 112t + 10
(B)
The maximum height occurs at the vertex of the height-vs.-time parabola, at
t = -b/(2a) = -112/[2(-16)] s = ? s
If you want the maximum height hmax, valuate h(t) at this value of t.