Inactive Tutor answered 04/27/20
(A)
h(t) = -16t2 + 112t + 10
(B)
The maximum height occurs at the vertex of the height-vs.-time parabola, at
t = -b/(2a) = -112/[2(-16)] s = ? s
If you want the maximum height hmax, valuate h(t) at this value of t.
Man M.
asked 04/26/20A toy rocket is launched vertically upward from a 10 foot platform with an initial velocity of 112 feet per second. Apply the vertical model equation; h= -16t^2 + V0t + h0
A) Write an equation for the situation?
B) After how many seconds will the rocket reach its absolute maximum height?
Inactive Tutor answered 04/27/20
(A)
h(t) = -16t2 + 112t + 10
(B)
The maximum height occurs at the vertex of the height-vs.-time parabola, at
t = -b/(2a) = -112/[2(-16)] s = ? s
If you want the maximum height hmax, valuate h(t) at this value of t.
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