Denise G. answered 04/21/20
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
The formula to use is
A=Aoekt
We can plug in the values we know and solve for k
1/2(15) = 15e12k 15 cancels
1/2= e12k Take the ln of both sides
ln(1/2) = ln(e12k) Apply exponent property
ln(1/2) = 12k(ln e) ln e=1
ln(1/2) = 12k Divide both sides by 12
k=-0.0578
Plug this in the equation
A=15e-0.0578t
For the next part, plug in 5 and solve for t using the same process as we used for k
5=15e-0.0578t Divide both sides by 15
(1/3) = e-0.0578t Take the ln of both sides
ln (1/3) = ln(e-0.0578t) Apply exponent property
ln (1/3) = -0.0578t ln(e) ln e=1
ln (1/3) = -0.0578t Divide both sides by -0.0578
t=19 years