n = 100 coin tosses
p = probability of getting heads
Expected Value (Mean): E[X] = np = (100)(0.7) = 70
Variance: Var[X] = np(1-p) = (100)(0.7)(0.3) = 21
Median of X is 70. However, we don't know if the binomial distribution is symmetrical (bell-shaped curve).
This tells you that in about 50% of all cases you will have less than 70 heads, and in the other ~50% of the cases you have 70 or more heads.
100
P(X ≥ 15): ∑x=15 (100 choose x) (0.7)x (0.3) 100-x