helpppppppppppppp

Question

The sum of three numbers is 117 The second number is 4 times the third. The third number is 9 more than the first. What are the numbers?

First number:
Second number:
Third number:

Answer 1

x = first number

y = second number

z = third number

sum of 3 numbers is 117

x+y+z = 117

second number is 4 times the third

y = 4z

third number is 9 more than the first

z = x+9

since y = 4z, y = 4(x+9) = 4x + 36

replacing y and z in terms of x in first equation:

x + (4x + 36) + (x + 9) = 117

6x + 45 = 117

6x = 72

x = 12

z= x + 9 = 12+9 = 21

y = 4z = 4 * 21 = 84

verify: 12 + 21 + 84 = 117