Probability homework

Question

At an amusement park, the probability that a child eats popcorn and cotton candy is 0.58. The probability that a child and eat popcorn is 0.69 and the probability that a child each cotton candy is 0.87. What is the probability that a child eats cotton candy Given that the child has already eaten popcorn?

A. 0.79

B. 0.84

C. 0.40

D. 0.67

Answer 1

This is a conditional probability. What is the probability of candy given popcorn. You divide the probability of event A and event B by the probability of event A. The intersection of event A and B in this problem is .58. Event A is .87. The answer is D.

Answer 2

P∩C = .58 Probability of eating Popcorn and Candy

P = .69 Probability of eating Popcorn

C = .87 Probability of eating Candy

Then P(P) = .58/.87 = .67 Probability that a child eats cotton candy Given that the child has already eaten popcorn