Chemistry MATH Question 1

Question

A rate is equal to 0.0200 M/s. If [A] = 0.100 M and rate = k[A]⁰[B]², what is the new rate if the concentration of [A] is increased to 0.200 M?

Answer 1

rate = k[B]² note that [A] is not included since it is zero order in A.

Therefore, the rate will be the same when [A] is 0.200 M as it is when [A] is 0.100 M, i.e. rate = 0.0200 M/s.