The sum of the roots is -B/A
2x2-5x+C=0
A=2
B=-5
Sum of α and β = -(-5)/2= 5/2
α + β = 5/2
Multiply both sides by 2
2α +2β = 5
4α -2β = 7
Elimination gives
6α=12
α=2
Substitution
2(2) +2β = 5
4+2β = 5
2β = 1
β = 1/2
The factors of the quadratic would need to be
(2x-1)(x-2)=0
Foil that
2x2-5x+2=0
C=2